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Question 1 of 10

1. Question

Directions:1-5) In the following questions, two equations I and II are given. You have to solve both the equations and give Answer as,

I. 3x^{2} +14x +15 =0

II. 3y^{2} -13y +14 =0

Correct

I. 3x^{2} +14x +15 =0

3x^{2} +9x +5x+15 =0

3x(x+3)+5(x+3) =0

(3x+5) (x+3) =0

X= -5/3, -3

II. 3y^{2} -13y +14 =0

3y^{2} -6y-7y +14 =0

3y(y-2)-7 (y-2) =0

(3y-7)(y-2) =0

Y= 7/3, 2

x<y

Incorrect

I. 3x^{2} +14x +15 =0

3x^{2} +9x +5x+15 =0

3x(x+3)+5(x+3) =0

(3x+5) (x+3) =0

X= -5/3, -3

II. 3y^{2} -13y +14 =0

3y^{2} -6y-7y +14 =0

3y(y-2)-7 (y-2) =0

(3y-7)(y-2) =0

Y= 7/3, 2

x<y

Question 2 of 10

2. Question

I. X^{3} =1331

II. 2y^{2} -21y +55 =0

Correct

I. X^{3} =1331

X = ∛1331 =11

II. 2y^{2} -21y +55 =0

2y^{2} -10y-11y+55 =0

2y(y-5)-11 (y-5) =0

(2y-11) (y-5) =0

Y= 11/2, 5

x>y

Incorrect

I. X^{3} =1331

X = ∛1331 =11

II. 2y^{2} -21y +55 =0

2y^{2} -10y-11y+55 =0

2y(y-5)-11 (y-5) =0

(2y-11) (y-5) =0

Y= 11/2, 5

x>y

Question 3 of 10

3. Question

I. 5x = 7y+21

II. 11x +4y+109 =0

Correct

I. 5x – 7y = 21 —> (1)

II. 11x +4y = -109 –> (2)

By solving the equation (1), (2), we get,

X= -7, y=-8

x>y

Incorrect

I. 5x – 7y = 21 —> (1)

II. 11x +4y = -109 –> (2)

By solving the equation (1), (2), we get,

X= -7, y=-8

x>y

Question 4 of 10

4. Question

I. 2x^{2} -11x +12 =0

II. 2y^{2} -17y +36 =0

Correct

I. 2x^{2} -11x +12 =0

2x^{2} -8x-3x +12 =0

2x(x-4)-3 (x-4) =0

(2x-3) (x-4) =0

X= 3/2, 4

II. 2y^{2} -17y +36 =0

2y^{2} -9y-8y +36 =0

Y(2y-9)-4(2y-9) =0

(y-4) (2y-9) =0

Y =4, 9/2

X<=y

Incorrect

I. 2x^{2} -11x +12 =0

2x^{2} -8x-3x +12 =0

2x(x-4)-3 (x-4) =0

(2x-3) (x-4) =0

X= 3/2, 4

II. 2y^{2} -17y +36 =0

2y^{2} -9y-8y +36 =0

Y(2y-9)-4(2y-9) =0

(y-4) (2y-9) =0

Y =4, 9/2

X<=y

Question 5 of 10

5. Question

I. 6x^{2} – 32x + 42 = 0

II. y^{2 }+ 7y + 12 = 0

Correct

I. 6x^{2} – 32x + 42 = 0

6x^{2} – 18x – 14x + 42 = 0

6x(x-3)-14 (x-3) =0

(6x – 14)(x – 3) = 0

x = 3, 7/3

II. y^{2 }+ 7y + 12 = 0

y^{2 }+ 3y+4y + 12 = 0

Y(y+3) +4 (y+3) =0

(y + 4)(y + 3) = 0

y = -4, -3

x > y

Incorrect

I. 6x^{2} – 32x + 42 = 0

6x^{2} – 18x – 14x + 42 = 0

6x(x-3)-14 (x-3) =0

(6x – 14)(x – 3) = 0

x = 3, 7/3

II. y^{2 }+ 7y + 12 = 0

y^{2 }+ 3y+4y + 12 = 0

Y(y+3) +4 (y+3) =0

(y + 4)(y + 3) = 0

y = -4, -3

x > y

Question 6 of 10

6. Question

Directions:6-10) In each of the following questions, two equations (i) and (ii) are given. You have to solve them and find the correct option.

I. 5x^{2}-13x-6=0

II. 6y^{2}+29y+35=0

Correct

I. 5x^{2}-13x-6=0

5x^{2}-15x+2x-6=0

(5x+2)(x-3)=0

x=-2/5 or 3

II. 6y^{2}+29y+35=0

6y^{2}+15y+14y+35=0

y=-5/2 or -7/3

Hence x>y

Incorrect

I. 5x^{2}-13x-6=0

5x^{2}-15x+2x-6=0

(5x+2)(x-3)=0

x=-2/5 or 3

II. 6y^{2}+29y+35=0

6y^{2}+15y+14y+35=0

y=-5/2 or -7/3

Hence x>y

Question 7 of 10

7. Question

I. 12x-14y+38=0

II. 4x+7y-209=0

Correct

12x -14y+38=0 ……….. (1)

4x+7y-209=0 ……………… (2)

Multiplying (2) by 2 and adding to (1), we have

x= 19 and y= 19

Thus x= y

Incorrect

12x -14y+38=0 ……….. (1)

4x+7y-209=0 ……………… (2)

Multiplying (2) by 2 and adding to (1), we have

x= 19 and y= 19

Thus x= y

Question 8 of 10

8. Question

I. x^{2}+28y+195=0

II. y^{2}-4y-221=0

Correct

I. x^{2}+28y+195=0

(x+13)(x+15)=0

x=-13 or -15

II. y^{2}-4y-221=0

(y-17)(y+13)=0

y=-13 or 17

Hence x≤y

Incorrect

I. x^{2}+28y+195=0

(x+13)(x+15)=0

x=-13 or -15

II. y^{2}-4y-221=0

(y-17)(y+13)=0

y=-13 or 17

Hence x≤y

Question 9 of 10

9. Question

I. 20x^{2}+27x+9=0

II. 2y^{2}-39y+54=0

Correct

I. 20x^{2}+27x+9=0

20x^{2}+15x+12x +9=0

x=-3/5 or -3/4

II. 2y^{2}-39y+54=0

2y^{2}-36y-3y+54=0

(2y-3)(y-18)=0

y= 1.5 and 18

Hence x<y

Incorrect

I. 20x^{2}+27x+9=0

20x^{2}+15x+12x +9=0

x=-3/5 or -3/4

II. 2y^{2}-39y+54=0

2y^{2}-36y-3y+54=0

(2y-3)(y-18)=0

y= 1.5 and 18

Hence x<y

Question 10 of 10

10. Question

I. 7x+8y=42

II. 3x+5y=18

Correct

7x+8y=42 ………….. (1)

3x+5y=18 ………….. (2)

Multiplying (1) by 3 and (2) by 7, and after solving them we have

x= 6 and y=0

Thus x>y

Incorrect

7x+8y=42 ………….. (1)

3x+5y=18 ………….. (2)

Multiplying (1) by 3 and (2) by 7, and after solving them we have