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Question 1 of 10
1. Question
Directions:1-5) In the following questions, two equations I and II are given. You have to solve both the equations.
Give Answer
I. 15a2 – 10a – 5 = 0;
II. 20b2 + 18b + 4 = 0
Correct
15 a2 + 15a – 5a – 5 = 0
15a (a + 1) – 5 (a + 1) = 0
(15a – 5) (a + 1) = 0
a = 1/3, -1
20b2 + 10b + 8b + 4 = 0
10b (2b +1) + 4 (2b + 1) = 0
(10b + 4) (2b + 1) = 0
b = -2/5, -1/2
Hence there is no relation.
Incorrect
15 a2 + 15a – 5a – 5 = 0
15a (a + 1) – 5 (a + 1) = 0
(15a – 5) (a + 1) = 0
a = 1/3, -1
20b2 + 10b + 8b + 4 = 0
10b (2b +1) + 4 (2b + 1) = 0
(10b + 4) (2b + 1) = 0
b = -2/5, -1/2
Hence there is no relation.
Question 2 of 10
2. Question
I. 26a2 – 88 = 16;
II. 3√b/8 – √b/4 = 1/√b
Correct
26a2 = 16 + 88 = 104
a2 = 104/26 = 4
a = ±2
3√b/8 – 2√b/8 = 1/√b
√b/8 = 1/√b
b = 8
a < b.
Incorrect
26a2 = 16 + 88 = 104
a2 = 104/26 = 4
a = ±2
3√b/8 – 2√b/8 = 1/√b
√b/8 = 1/√b
b = 8
a < b.
Question 3 of 10
3. Question
I. 2a + 3b = 20;
II. 4a + 2b = 24
Correct
4a + 6b = 40 —-I
4a + 2b = 24 —-II
Solve I and II we get
4b = 16
b = 4
Apply the b = 4 in eqn I
a = 4
a= b.
Incorrect
4a + 6b = 40 —-I
4a + 2b = 24 —-II
Solve I and II we get
4b = 16
b = 4
Apply the b = 4 in eqn I
a = 4
a= b.
Question 4 of 10
4. Question
I. 10a2 + 9a -7 = 0;
II. 12b + 84 = 122
Correct
10a2 + 14a – 5a – 7 = 0
2a (5a + 7) – 1 (5a + 7) = 0
(2a – 1) (5a + 7) = 0
a = 1/2, -7/5
12b = 144 – 84 = 60
b = 60/12 = 5
a < b.
Incorrect
10a2 + 14a – 5a – 7 = 0
2a (5a + 7) – 1 (5a + 7) = 0
(2a – 1) (5a + 7) = 0
a = 1/2, -7/5
12b = 144 – 84 = 60
b = 60/12 = 5
a < b.
Question 5 of 10
5. Question
I. a2 = 196;
II. b2 + 11b + 24 = 0
Correct
a = ±14
b2 + 8b + 3b + 24 = 0
b (b + 8) + 3 (b + 8) = 0
(b + 3) (b + 8) = 0
b = -3, -8
Hence there is no relation.
Incorrect
a = ±14
b2 + 8b + 3b + 24 = 0
b (b + 8) + 3 (b + 8) = 0
(b + 3) (b + 8) = 0
b = -3, -8
Hence there is no relation.
Question 6 of 10
6. Question
Directions:6-10) In each of the following questions, two equations (i) and (ii) are given. You have to solve them and find the correct option.
i) 2x2+11x+12=0
ii) x2+2x-35=0
Correct
a) 2x2+11x+12=0
2x2+8x+3x+12=0
(x+4)(2x+3)=0
x= -4 and -3/2
b) x2+2x-35=0
x2+7x-5x-35=0
(x+7)(x-5)=0
x=-7 or 5
Hence the relationship cannot be determined
Incorrect
a) 2x2+11x+12=0
2x2+8x+3x+12=0
(x+4)(2x+3)=0
x= -4 and -3/2
b) x2+2x-35=0
x2+7x-5x-35=0
(x+7)(x-5)=0
x=-7 or 5
Hence the relationship cannot be determined
Question 7 of 10
7. Question
i) x2-20x+99=0
ii) 2y2-15y+28=0
Correct
a) x2-20x+99=0
x2-9x-11x+99=0
(x-9)(x-11)=0
x=9 and 11
b) 2y2-15y+28=0
2y2-8y-7y+28=0
(y-4)(2y-7)=0
y= 7/2 and 4
Thus x>y
Incorrect
a) x2-20x+99=0
x2-9x-11x+99=0
(x-9)(x-11)=0
x=9 and 11
b) 2y2-15y+28=0
2y2-8y-7y+28=0
(y-4)(2y-7)=0
y= 7/2 and 4
Thus x>y
Question 8 of 10
8. Question
i) 2x+5y-√2601=0
ii) 7x+3y-77=0
Correct
After solving above equations we have x= 8 and y=7
Hence x>y
Incorrect
After solving above equations we have x= 8 and y=7
