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- Question 1 of 10
##### 1. Question

Directions:1-10)

**In each of the following questions, two equations(i) and (ii) are given. You have to solve them and find the correct option**.a) x

^{3 }– 39304 = 0b) y

^{2 }– 1296=0Correcta) x

^{3 }– 39304 = 0x

^{3 }= 39304x=34

b) 2y

^{2 }– 5184=0y

^{2 }=1296y=±36

Thus,

**the relationship cannot be determined**.Incorrecta) x

^{3 }– 39304 = 0x

^{3 }= 39304x=34

b) 2y

^{2 }– 5184=0y

^{2 }=1296y=±36

Thus,

**the relationship cannot be determined**. - Question 2 of 10
##### 2. Question

a) 624-342-120+88x =784+248+516+22

b) (21y-504)(18y-576)=0

Correcta) 624-342-120+88x =784+248+516+22

624+88x= 2032

88x=1408

x=16

b) (21y-504)(18y-576)=0

21y- 504=0, 18y-576=0

21y=504, 18y=576

y=24 and 32

Thus

**x<y**Incorrecta) 624-342-120+88x =784+248+516+22

624+88x= 2032

88x=1408

x=16

b) (21y-504)(18y-576)=0

21y- 504=0, 18y-576=0

21y=504, 18y=576

y=24 and 32

Thus

**x<y** - Question 3 of 10
##### 3. Question

a) 26x^2-64x+24=0

b) 2y^2-28y+96=0

Correcta) 26x^2-64x+24=0

13x^2-32x+12=0

(X-2)(13x-6)=0

x=2 and 6/13

b) 2^2-28y+96=0

y^2-14y+48=0

(y-6)(y-8)=0

y=6 and 8

Thus

**x<y**Incorrecta) 26x^2-64x+24=0

13x^2-32x+12=0

(X-2)(13x-6)=0

x=2 and 6/13

b) 2^2-28y+96=0

y^2-14y+48=0

(y-6)(y-8)=0

y=6 and 8

Thus

**x<y** - Question 4 of 10
##### 4. Question

a) 16y + 10x=48

b) 8y+7x=32

Correct10x+16y=48……(1)

7x+8y=32………(2)

Multiplying (2) by 2 and solving equations, we get

x=4 and y=0.5

Thus

**x>y**Incorrect10x+16y=48……(1)

7x+8y=32………(2)

Multiplying (2) by 2 and solving equations, we get

x=4 and y=0.5

Thus

**x>y** - Question 5 of 10
##### 5. Question

a) 2x^2+11x+9=0

b)2y^2-7y+6=0

Correcta) 2x^2+11x+9=0

2x(x+1) +9(x+1) =0

(x+1)(2x+9)=0

x=-4.5 and -1

b) 2y^2-7y+6=0

2y^2-4y-3y+6=0

2y(y-2)-3(y-2) =0

y=1.5 and 2

Thus

**x<y**Incorrecta) 2x^2+11x+9=0

2x(x+1) +9(x+1) =0

(x+1)(2x+9)=0

x=-4.5 and -1

b) 2y^2-7y+6=0

2y^2-4y-3y+6=0

2y(y-2)-3(y-2) =0

y=1.5 and 2

Thus

**x<y** - Question 6 of 10
##### 6. Question

**Direction (6-10):****In the following questions, two equations I and II are given. You have to solve both the equations.**

**Give Answer**

I. p^{2}– 18p + 72= 0

II. 5q^{2}– 18q + 9 = 0Correctp

^{2}– 18p + 72= 0

(p-12)(p-6) = 0

Gives p = 6, 12

5q^{2}– 18q + 9 = 0

5q^{2}– 15q – 3q + 9 = 0

5q (q-3) – 3(q-3) =0

(5q-3) (q-3) =0

Gives q = 3/5, 3

Put on number line

3/5 3 6 12

P > qIncorrectp

^{2}– 18p + 72= 0

(p-12)(p-6) = 0

Gives p = 6, 12

5q^{2}– 18q + 9 = 0

5q^{2}– 15q – 3q + 9 = 0

5q (q-3) – 3(q-3) =0

(5q-3) (q-3) =0

Gives q = 3/5, 3

Put on number line

3/5 3 6 12

P > q - Question 7 of 10
##### 7. Question

I. p

^{2}= 4

II. 3q^{2}– 4q – 4 = 0Correctp

^{2}= 4

Gives p = 2 , -2

3q^{2}– 4q – 4 = 0

3q^{2}– 6q + 2q – 4 = 0

Gives q = -2/3, 2

Put on number line

-2 -2/3 2

So no relationIncorrectp

^{2}= 4

Gives p = 2 , -2

3q^{2}– 4q – 4 = 0

3q^{2}– 6q + 2q – 4 = 0

Gives q = -2/3, 2

Put on number line

-2 -2/3 2

So no relation - Question 8 of 10
##### 8. Question

I. 6p

^{2}– 5p – 6 = 0

II. 2q^{2}– 13q + 20 = 0Correct6p

^{2}– 5p – 6 = 0

6p^{2}– 9p + 4p – 6 = 0

Gives p = -2/3, 3/2

2q^{2}– 13q + 20 = 0

2q^{2}– 8q – 5q +20 = 0

Gives q = 4, 5/2

Put on number line

-2/3 3/2 5/2 4

P < qIncorrect6p

^{2}– 5p – 6 = 0

6p^{2}– 9p + 4p – 6 = 0

Gives p = -2/3, 3/2

2q^{2}– 13q + 20 = 0

2q^{2}– 8q – 5q +20 = 0

Gives q = 4, 5/2

Put on number line

-2/3 3/2 5/2 4

P < q - Question 9 of 10
##### 9. Question

I. 2p

^{2}– 5p = 0

II. 3q^{2}– 7q – 6 = 0Correct2p

^{2}– 5p = 0

p(2p-5) = 0

Gives p = 0, 5/2

3q^{2}– 7q – 6 = 0

3q^{2}– 9q + 2q – 6 = 0

Gives q = -2/3, 3

Put on number line

-2/3 0 5/2 3

There is no relationIncorrect2p

^{2}– 5p = 0

p(2p-5) = 0

Gives p = 0, 5/2

3q^{2}– 7q – 6 = 0

3q^{2}– 9q + 2q – 6 = 0

Gives q = -2/3, 3

Put on number line

-2/3 0 5/2 3

There is no relation - Question 10 of 10
##### 10. Question

I. 2p

^{2}+ 5p + 2= 0

II. 2q^{2}+ 19q + 45 = 0Correct2p

^{2}+ 5p + 2= 0

2p^{2}+ 4p + p + 2= 0

Gives p = -1/2, -2

2q^{2}+ 19q + 45 = 0

2q^{2}+ 10q + 9q + 45 = 0

Gives q= -10/2, -9/2

Put on number line

-10/2 -9/2 -2 -1/2

P > qIncorrect2p

^{2}+ 5p + 2= 0

2p^{2}+ 4p + p + 2= 0

Gives p = -1/2, -2

2q^{2}+ 19q + 45 = 0

2q^{2}+ 10q + 9q + 45 = 0

Gives q= -10/2, -9/2

Put on number line

-10/2 -9/2 -2 -1/2

P > q