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- Question 1 of 10
1. Question
Directions:1-5)In the following questions, two equations I and II are given. You have to solve both the equations and give Answer as,In the following questions, two equations I and II are given. You have to solve both the equations and give Answer as,
- √324 x + √11664 = 0
- (16807)1/5 y + (9261)1/3 = 0
Correct- √324 x + √11664 = 0
18x + 108 = 0
18x = -108
x = – 6
II. (16807)1/5 y + (9261)1/3 = 0
(75)1/5y + (213)1/3 = 0
7y + 21 = 0
7y = -21
y = -3
Hence x < y
Incorrect- √324 x + √11664 = 0
18x + 108 = 0
18x = -108
x = – 6
II. (16807)1/5 y + (9261)1/3 = 0
(75)1/5y + (213)1/3 = 0
7y + 21 = 0
7y = -21
y = -3
Hence x < y
- Question 2 of 10
2. Question
- 2x – y = 31
- y = ∛19683
Correct- y = ∛19683
y = 27
II. 2x – y = 31
2x – 27 = 31
2x = 58
x = 29
Hence x > y
Incorrect- y = ∛19683
y = 27
II. 2x – y = 31
2x – 27 = 31
2x = 58
x = 29
Hence x > y
- Question 3 of 10
3. Question
- x2 – 10x + 21 = 0
- y2 – 10y + 16 = 0
Correct- x2 – 10x + 21 = 0
(x – 7) (x – 3) = 0
x = 7, 3
II. y2 – 10y + 16 = 0
(y -8) (y – 2) = 0
y = 8, 2
Hence the relationship can’t be determined.
Incorrect- x2 – 10x + 21 = 0
(x – 7) (x – 3) = 0
x = 7, 3
II. y2 – 10y + 16 = 0
(y -8) (y – 2) = 0
y = 8, 2
Hence the relationship can’t be determined.
- Question 4 of 10
4. Question
- 12x2 – 17x – 57 = 0
- 4y2 -7y – 36 = 0
Correct- 12x2 – 17x – 57 = 0
12x2 – 36x + 19x – 57 = 0
12x(x – 3) + 19(x – 3) = 0
(12x + 19) (x – 3) = 0
x = -19/12, 3
x = -1.58, 3
II.4y2 -7y – 36 = 0
4y2 -16y + 9y -36 = 0
4y(y – 4) + 9(y – 4) = 0
(4y + 9) (y – 4) = 0
y = -9/4, 4
y= -2.25, 4
Hence the relationship can’t be determined.
Incorrect- 12x2 – 17x – 57 = 0
12x2 – 36x + 19x – 57 = 0
12x(x – 3) + 19(x – 3) = 0
(12x + 19) (x – 3) = 0
x = -19/12, 3
x = -1.58, 3
II.4y2 -7y – 36 = 0
4y2 -16y + 9y -36 = 0
4y(y – 4) + 9(y – 4) = 0
(4y + 9) (y – 4) = 0
y = -9/4, 4
y= -2.25, 4
Hence the relationship can’t be determined.
- Question 5 of 10
5. Question
- 3x + 5y = 34
- 5x – 2y = 5
Correct3x + 5y = 34 –à (1)
5x – 2y = 5—à (2)
By solving the equation (1) and (2), we get,
x = 3, y = 5
Hence x < y
Incorrect3x + 5y = 34 –à (1)
5x – 2y = 5—à (2)
By solving the equation (1) and (2), we get,
x = 3, y = 5
Hence x < y
- Question 6 of 10
6. Question
Directions:6-10) In the following questions, two equations numbered I and II are given. You have to solve both the equations and Give Answer If
- x2 – 452 = 874 -√900
- y = (24+√(121+√(500+29)))
Correct- x2 – 452 = 874 -√900
x2 = 1326 – 30 = 1296
x =± 36
- y = (24+√(121+√(500+29)))
y = (24+√(121+23))
y = (24+12)
y = 36
x ≤ y
Incorrect- x2 – 452 = 874 -√900
x2 = 1326 – 30 = 1296
x =± 36
- y = (24+√(121+√(500+29)))
y = (24+√(121+23))
y = (24+12)
y = 36
x ≤ y
- Question 7 of 10
7. Question
- 3 + 18/x + 15/x2 =0
II. 2 + 4/y+2/y2 =0
Correct- 3 + 18/x + 15/x2 =0
3x2 + 18x + 15 =0
3x2 + 3x + 15x +15 =0
3x (x+1) +15 (x+1) =0
(3x+15) (x+1) =0
x =-1, -15/3 = -1, -5
- 2 + 4/y+2/y2 =0
2y2 + 4y + 2 =0
2y2 +2y +2y +2 =0
2y (y+1) +2 (y+1) =0
(2y+2) (y+1) =0
y = -1, -2/2 = -1, -1
x ≤ y
Incorrect- 3 + 18/x + 15/x2 =0
3x2 + 18x + 15 =0
3x2 + 3x + 15x +15 =0
3x (x+1) +15 (x+1) =0
(3x+15) (x+1) =0
x =-1, -15/3 = -1, -5
- 2 + 4/y+2/y2 =0
2y2 + 4y + 2 =0
2y2 +2y +2y +2 =0
2y (y+1) +2 (y+1) =0
(2y+2) (y+1) =0
y = -1, -2/2 = -1, -1
x ≤ y
- Question 8 of 10
8. Question
- x3 = 512
II. y2 – 17y + 72 =0
Correct- x3 = 512
x = 8
- y2 – 17y + 72 =0
y2 – 8y – 9y+ 72 =0
(y-8) (y-9) =0
y = 8, 9
x ≤ y
Incorrect- x3 = 512
x = 8
- y2 – 17y + 72 =0
y2 – 8y – 9y+ 72 =0
(y-8) (y-9) =0
y = 8, 9
x ≤ y
- Question 9 of 10
9. Question
- 9x+7y = 25
II. 5x+14y = 24
Correct9x+7y = 25 —– (1)
5x+14y = 24 —– (2)
Simplify the above equation, we get x = 2 and y =1
x > y
Incorrect9x+7y = 25 —– (1)
5x+14y = 24 —– (2)
Simplify the above equation, we get x = 2 and y =1
x > y
- Question 10 of 10
10. Question
- 15x2 – 25x + 10 = 12x2-6x -6
- 2y2 + 45y + 252 =0
Correct- 15x2 – 25x + 10 = 12x2-6x -6
3x2 – 19x + 16 =0
3x2 -3x – 16x + 16 =0
(3x-16) (x-1) =0
x=16/3, 1 = 5.33, 1
- 2y2 + 45y + 252 =0
2y2 + 24y +21y + 252 =0
2y (y+12) + 21 (y+12) =0
(2y+21) (y+12) =0
y= -21/2, -12 = -10.5, -12
x > y
Incorrect- 15x2 – 25x + 10 = 12x2-6x -6
3x2 – 19x + 16 =0
3x2 -3x – 16x + 16 =0
(3x-16) (x-1) =0
x=16/3, 1 = 5.33, 1
- 2y2 + 45y + 252 =0
2y2 + 24y +21y + 252 =0
2y (y+12) + 21 (y+12) =0
(2y+21) (y+12) =0
y= -21/2, -12 = -10.5, -12
x > y
