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Question 1 of 10

1. Question

Directions:1-5) In each of the following questions, two equations (a) and (b) are given. Solve them and find the correct option.

I. x^{4}= 28561

II. [(y^{5/2})/√13] = [(2*4) +√25]^{2}

Correct

I. x^{4}= 28561

x= 13 and -13

II. [(y^{5/2})/√13] = [(2*4)+√25]^{2}

[(y^{5/2})/√13]= [8+5]^{2}

y^{5/2}= 13^{1/2}(13)^{2}

y=13

Hence x ≤ y

Incorrect

I. x^{4}= 28561

x= 13 and -13

II. [(y^{5/2})/√13] = [(2*4)+√25]^{2}

[(y^{5/2})/√13]= [8+5]^{2}

y^{5/2}= 13^{1/2}(13)^{2}

y=13

Hence x ≤ y

Question 2 of 10

2. Question

I. 3x-2y=12

II. 7x-6y=18

Correct

3x-2y=12………… (1)

7x-6y=18………… (2)

Multiply (1) by 3 then we get,

9x-6y=36 ……………. (3)

After solving (2) and (3), we get, x=9 and y=7.5

Hence, x>y

Incorrect

3x-2y=12………… (1)

7x-6y=18………… (2)

Multiply (1) by 3 then we get,

9x-6y=36 ……………. (3)

After solving (2) and (3), we get, x=9 and y=7.5

Hence, x>y

Question 3 of 10

3. Question

I. 8x^{2}-34x=- 8

II. 23y^{2}-368=0

Correct

I. 8x^{2}-34x=-8

8x^{2}-34x+8=0

8x^{2}-32x-2x+8=0

8x(x-4)-2(x-4) =0

x=4 and ¼

II. 23y^{2}-368=0

23y^{2}=368

y^{2}=16

y=4 and -4

Hence, the relationship cannot be determined

Incorrect

I. 8x^{2}-34x=-8

8x^{2}-34x+8=0

8x^{2}-32x-2x+8=0

8x(x-4)-2(x-4) =0

x=4 and ¼

II. 23y^{2}-368=0

23y^{2}=368

y^{2}=16

y=4 and -4

Hence, the relationship cannot be determined

Question 4 of 10

4. Question

I. x^{2}+12x+36=0

II. y^{2}+7y+6=0

Correct

I. x^{2}+12x+36=0

x^{2}+6x+6x+36=0

x(x+6)+6(x+6)=0

x=-6 and -6

II. y^{2}+7y+6=0

y^{2 }+y+6y+6=0

y(y+1)+6(y+1)=0

y=-1 and -6

Hence, x≤y

Incorrect

I. x^{2}+12x+36=0

x^{2}+6x+6x+36=0

x(x+6)+6(x+6)=0

x=-6 and -6

II. y^{2}+7y+6=0

y^{2 }+y+6y+6=0

y(y+1)+6(y+1)=0

y=-1 and -6

Hence, x≤y

Question 5 of 10

5. Question

I. √360 x + (200)^{1/2}=0

II. √500 y + √402=0

Correct

I. √360 x + (200)^{1/2}=0

√360 x=-√200

x=-0.74

II. √500 y + √402=0

√500 y= -√402

y=-√402/√500

y=-0.89

Hence, x>y

Incorrect

I. √360 x + (200)^{1/2}=0

√360 x=-√200

x=-0.74

II. √500 y + √402=0

√500 y= -√402

y=-√402/√500

y=-0.89

Hence, x>y

Question 6 of 10

6. Question

Directions:6-10) In each of the following questions, two equations (a) and (b) are given. You have to solve them and find the correct option.

a)x^{3 }– 39304 = 0

b)y^{2 }– 1296=0

Correct

x^{3 }– 39304 = 0

x^{3 }= 39304

x=34

2y^{2 }– 5184=0

y^{2 }=1296

y=±36

Thus, the relationship cannot be determined.

Incorrect

x^{3 }– 39304 = 0

x^{3 }= 39304

x=34

2y^{2 }– 5184=0

y^{2 }=1296

y=±36

Thus, the relationship cannot be determined.

Question 7 of 10

7. Question

a)624-342-120+88x=784+248+516+22

b)(21y-504)(18y-576)=0

Correct

624-342-120+88x =784+248+516+22

624+88x= 2032

88x=1408

x=16

(21y-504)(18y-576)=0

21y- 504=0, 18y-576=0

21y=504, 18y=576

y=24 and 32

Thus x<y

Incorrect

624-342-120+88x =784+248+516+22

624+88x= 2032

88x=1408

x=16

(21y-504)(18y-576)=0

21y- 504=0, 18y-576=0

21y=504, 18y=576

y=24 and 32

Thus x<y

Question 8 of 10

8. Question

a)26x^{2}-64x+24=0

b)2y^{2}-28y+96=0

Correct

26x^{2}-64x+24=0

13x^{2}-32x+12=0

(X-2)(13x-6)=0

x=2 and 6/13

b) 2^{2}-28y+96=0

y^{2}-14y+48=0

(y-6)(y-8)=0

y=6 and 8

Thus x<y

Incorrect

26x^{2}-64x+24=0

13x^{2}-32x+12=0

(X-2)(13x-6)=0

x=2 and 6/13

b) 2^{2}-28y+96=0

y^{2}-14y+48=0

(y-6)(y-8)=0

y=6 and 8

Thus x<y

Question 9 of 10

9. Question

a)16y + 10x=48

b)8y+7x=32

Correct

10x+16y=48……(1)

7x+8y=32………(2)

Multiplying (2) by 2 and solving equations, we get

x=4 and y=0.5

Thus x>y

Incorrect

10x+16y=48……(1)

7x+8y=32………(2)

Multiplying (2) by 2 and solving equations, we get