# Set-12 Quadratic Equations (Inequalities) For SBI PO and SBI Clerk 2019 | Must Go Through These Questions Dear Aspirants,
We are providing the most important Quadratic Equations (Inequalities) for SBI PO 2019, SBI Clerk 2019 and all other competitive bank and insurance exams. These questions have very high chances to be asked in SBI PO 2019, SBI Clerk 2019.
Get the Best Test Series for SBI PO 2019 at the most affordable price (Based on Real Exam Pattern) – Click Here
Download the Best GK Gaming App for Current Affairs and GK (Bank+SSC)– Click here (App No 1)       (App No 2)

Directions:1-10) In each of these questions two equations (I) and (II) are given. You have to solve both the equations and give answer.

1.

1. x^2 – 26x + 168 = 0
2. y^2 – 25y + 156 = 0

2.

1. 6x – 5y = -47
2. 5x + 3y = 11

3.

I.2.3x – 20.01 = 0

II.2.9y – x = 0

4.

1. x = √1764
2. y^2 = 1764

5.

1. x^2 – 13x + 42 = 0
2. y^2 + y – 42 = 0

6.

1. 77X2 + 58X +8=0
2. 56Y2+29Y +3=0

7.

1. 43X2 – 90X +8=0
2. 56Y2-36Y +4=0

8.

I. 34X2 – 140X +16=0

II. 24Y2-55Y+26=0

9.

1. 28X2 – 75X +17=0
2. 36Y2-71Y +14=0

10.

1. 19X2 – 84X +32=0
2. 17Y2-75Y +28=0

Check your Answers below:

1. Directions:1-10) In each of these questions two equations (I) and (II) are given. You have to solve both the equations and give answer.

##### 1. Question
1. x^2 – 26x + 168 = 0
2. y^2 – 25y + 156 = 0
Ans:5

1. x^2 – 26x + 168 = 0

X^2 – 12x – 14x + 168 = 0

x (x – 12) – 14(x – 12) = 0

(x – 12) (x – 14) = 0

x = 12, 14

II.y^2 – 25y + 156 = 0

y^2 – 13y – 12y + 156 = 0

y(y – 13) – 12(y – 13) = 0

(y – 12) (y – 13) = 0

y = 12, 13

Hence, no relation can be established between x and y

2. ##### 2. Question
1. 6x – 5y = -47
2. 5x + 3y = 11
Ans:3
Equation (I) × 3 = 18x – 15y = -141

Equation (II) × 5 = 25x + 15y = 55

43x = -86

X = – 86/43 = 2

From II, we have,

5x + 3y = 11

3y = 11 – 5x

3y = 11 + 10

3y = 21

y = 7

Hence x < y

3. ##### 3. Question

I.2.3x – 20.01 = 0

II.2.9y – x = 0

Ans:1
I.2.3x – 20.01 = 0

X = 20.01 / 2.3 = 8.7

II.2.9y – x = 0

or, x = 2.9y

y = 8.7 /2.9 = 3

Hence x > y

4. ##### 4. Question
1. x = √1764
2. y^2 = 1764
Ans:2
I.x = 1764

x = 42

II.y^2 = 1764

y = + 42

Hence x ≥ y

5. ##### 5. Question
1. x^2 – 13x + 42 = 0
2. y^2 + y – 42 = 0
Ans:2
I.x^2 – 13x + 42 = 0

x^2 – 6x – 7x + 42 = 0

x(x – 6) – 7(x – 6) = 0

(x – 6) (x – 7) = 0

x = 6, 7

II.y^2 + y – 42 = 0

y^2 + 7y – 6x – 42 = 0

y(y + 7) – 6(y + 7) = 0

(y – 6)(y + 7) = 0

y = 6, – 7

Hence x ≥ y

6. ##### 6. Question
1. 77X2 + 58X +8=0
2. 56Y2+29Y +3=0
Ans:5

1. 77X2 + 58X +8=0
2. 56Y2+29Y +3=0

Sol: I. 77X2 + 58X +8=0

Or, 77X2+44X+14X+8=0

Or, 11X(7X+4)+2(7X+4)=0

Or, (11X+2)(7X+4)=0

Or, X= (-2)/11  ,  (-4)/7

1. 56Y2+29Y +3=0

Or, 56Y2+8Y+21Y+3=0

Or, 8Y(7Y+1)+3(7Y+1)=0

Or, (8Y+3)(7Y+1)=0

Or,  Y= (-3)/8  ,  (-1)/7

Hence, on relationship between x and y cannot be established

7. ##### 7. Question
1. 43X2 – 90X +8=0
2. 56Y2-36Y +4=0
Ans:5

1. 43X2 – 90X +8=0
2. 56Y2-36Y +4=0

Sol: I. 43X2 – 90X +8=0

Or, 43X2-86X-4X+8=0

Or, 43X(X-2)-4(X-2)=0

Or, (43X-4)(X-2)=0

Or, X= 2 , 4/43

1. 56Y2-36Y +4=0

Or, 56Y2-28Y-8Y+4=0

Or, 28Y(2Y-1)-4(2Y-1)=0

Or, (28Y-4)(2Y-1)=0

Or, Y = 4/28, 1/2

Hence, on relationship between x and y cannot be established

8. ##### 8. Question

I. 34X2 – 140X +16=0

II. 24Y2-55Y+26=0

Ans:5

1. 34X2 – 140X +16=0
2. 24Y2-55Y+26=0

Sol: I. 34X2 – 140X +16=0

Or, 34X2-136X-4X+16=0

Or, 34X(X-4)-4(X-4)=0

Or, (34X-4)(X-4)=0

Or, X = 4, 4/34

1. 24Y2-55Y+26=0

Or, 24Y2-16Y-39Y+26=0

Or, 8Y(3Y-2)-13(3Y-2)=0

Or, (8Y-13)(3Y-2)=0

Or, Y=2/3, 13/8

Hence, on relationship between x and y cannot be established

9. ##### 9. Question
1. 28X2 – 75X +17=0
2. 36Y2-71Y +14=0
Ans:5

1. 28X2 – 75X +17=0
2. 36Y2-71Y +14=0

Sol: I. 28X2 – 75X +17=0

Or, 28X2-7X-68X+17=0

Or, 7X(4X-1)-17(4X-1)=0

Or, (7X-17)(4X-1)=0

Or, X= 17/7, 1/4

1. 36Y2-71Y +14=0

Or, 36Y2-8Y-63Y+14=0

Or, 4Y(9Y-2)-7(9Y-2)=0

Or, (4Y-7)(9Y-2)=0

Or, Y = 7/4  ,  2/9

Hence, on relationship between x and y cannot be established

10. ##### 10. Question
1. 19X2 – 84X +32=0
2. 17Y2-75Y +28=0
Ans:5

1. 19X2 – 84X +32=0
2. 17Y2-75Y +28=0

Sol: I. 19X2 – 84X +32=0

Or, 19X2-76X-8X+32=0

Or, 19X(X-4)-8(X-4)=0

Or, (19X-8)(X-4)=0

Or, X= 4 , 8/19

1. 17Y2-75Y +28=0

Or, 17Y2– 68Y-7Y+28=0

Or, 17Y(Y-4)-7(Y-4)=0

Or, (17Y-7)(Y-4)=0

Or, Y= 4 ,7/17

Cannot be determined #### About Study Virus

View all posts by Study Virus →

This site uses Akismet to reduce spam. Learn how your comment data is processed.