# Set-17 Quadratic Equations (Inequalities) For SBI PO and SBI Clerk 2019 | Must Go Through These Questions Dear Aspirants,
We are providing the most important Quadratic Equations (Inequalities) for SBI PO 2019, SBI Clerk 2019 and all other competitive bank and insurance exams. These questions have very high chances to be asked in SBI PO 2019, SBI Clerk 2019.
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Directions:1-5) In the following question, two equations I and II are given. Solve both the equations carefully & answer the questions given below:If x > y

1.

I. X2+5 √3x -42 =0
II. Y2 -√2y -24 =0

2.

I. 5x – 2.2y = –17
II. 4x + 0.6y = 31

3.

I. 30×2+89x+58 =0
II. 27y2 -51y -56 =0

4.

I. X2 -4x +3.91 =0
II. Y2-6y +8.75 =0

5.

I. 78x2+199x+65 =0
II. 56y2+127y+72 =0

Directions: 6-10) In the following question, two equations I and II are given. Solve both the equations carefully & answer the questions given below:

6.

1. (x1/4 /20)2 = 196/X3/2
2. Y1/3*y2/3*143 = 7*y4

7.

1. 4/x1/2 +7/x1/2 = x1/2
2. Y2 – (115/2/y1/2) =0

8.

1. 5001/2x +4021/2 =0
2. 3601/2y +2001/2 =0

9.

1. X2-5 √3x -42 =0
2. 4 √3 y2 -5y -2 √3 =0

10.

1. (x+40)1/2 =2561/2 – 1211/2
2. Y2+576 =697

Check your Answers below:

• Directions:1-5) In the following question, two equations I and II are given. Solve both the equations carefully & answer the questions given below:If x > y

##### 1. Question

I. X2+5 √3x -42 =0

II. Y2 -√2y -24 =0

Ans:5
X2+5 3 X -42 =0(X +7 3) (X-2 3) =0

X =-7 3,, 23

Y2 2y -24 =0

Y2 – 4 2y +3 2y -24 =0

Y = 4 2, -3 2

The relationship cannot be determined

• ##### 2. Question

I. 5x – 2.2y = –17

II. 4x + 0.6y = 31

Ans:2
5x – 2.2y = –174x + 0.6y = 31

Simply the above equation, we get x= 10 and y = 15

x < y

• ##### 3. Question

I. 30×2+89x+58 =0

II. 27y2 -51y -56 =0

Ans:2
I. 30x2+89x +58 =030x2 +60x + 29x +58 =0

30x(x+2)+29 (x+2) =0

(30x+29) (x+2) =0

X = -29/30, -2

II. 27y2-51y -56 =0

27y2 -72y + 21y -56 =0

9y(3y -8) +7(3y-8) =0

(9y+7)(3y-8) =0

Y = -7/9, 8/3

X < Y

• ##### 4. Question

I. X2 -4x +3.91 =0

II. Y2-6y +8.75 =0

Ans:2
X2 -4x +3.91 =0X2-2.3x – 1.7x +3.91 =0

X(x-2.3) – 1.7 (x-3.91) =0

(x-1.7)(x-2.3) =0

X=2.3, 1.7

Y2-6y +8.75 =0

Y2-3.5y-2.5y+8.75 =0

Y (y-3.5) – 2.5 (y-3.5) =0

(y-3.5)(y-2.5)=0

Y=3.5, 2.5

x < y

• ##### 5. Question

I. 78x2+199x+65 =0

II. 56y2+127y+72 =0

Ans:5
I. 78x2+199x +65 =078x2 +169x+30x +65 =0

13x (6x+13) +5(6x+13) =0

(13x+5) (6x+13) =0

X= -5/13, -13/6

II. 56y2+127y +72 =0

56y2 +64y+63y +72 =0

8y (7y+8) +9(7y+8) =0

(8y+9)(7y+8) =0

Y= -9/8, -8/7

Relationship cannot be determined.

Directions: 6-10) In the following question, two equations I and II are given. Solve both the equations carefully & answer the questions given below:

##### 6. Question
1. (x1/4 /20)2 = 196/X3/2
2. Y1/3*y2/3*143 = 7*y4
Ans:5
(x1/4 /20)2 = 196/X3/2X1/2/202 =196 / X3/2

X2=78400

X = 280 , -280

Y1/3*y2/3*143 = 7*y4

Y*143=7 * y4

14*14*14/7 =y3

Y3= 196*2

Y3 =392

Y = 7.31 =7

The relation cannot be established

• ##### 7. Question
1. 4/x1/2 +7/x1/2 = x1/2
2. Y2 – (115/2/y1/2) =0
Ans:5
4/x1/2 +7/ x1/2 = x1/211 =X

Y2 – (115/2/y1/2) =0

Y5/2 =115/2

Y =11

x = y or relation cannot be established

• ##### 8. Question
1. 5001/2x +4021/2 =0
2. 3601/2y +2001/2 =0
Ans:2
5001/2x +4021/2 =0X = – (402/500)1/2

X = – 20/22 = -10/11

3601/2y +2001/2 =0

Y = – ( 200/360 )1/2 = – 14/19

x < y

• ##### 9. Question
1. X2-5 √3x -42 =0
2. 4 √3 y2 -5y -2 √3 =0
Ans:5
X2+5 3 X -42 =0(X +7 3) (X-23) =0

X =-7 3 , 23

4 3Y2 -5y -2 3 =0

Y = +8 /43 , -3 / 4 3

x = y or relation cannot be established

• ##### 10. Question
1. (x+40)1/2 =2561/2 – 1211/2
2. Y2+576 =697
Ans:2
(x+40)1/2 =2561/2 – 1211/2X+40 =25

X=-15

Y2+576 =697

Y2 =121

Y =11 ,-11

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