# Set-22 Inequalities For SBI PO and SBI Clerk 2019 | Must Go Through These Questions

Dear Aspirants,
We are providing the most important Inequalities for SBI PO 2019, SBI Clerk 2019 and all other competitive bank and insurance exams. These questions have very high chances to be asked in SBI PO 2019, SBI Clerk 2019.

Directions:(1-10) In these questions, relationship between different elements is shown in the statements. These statements are followed by two conclusions.
1.
Statements:
P ≤ Q < R > S; T ≥ Q < U = V
Conclusions:
I. V > P
II. R < U

2.
Statements:
A ≤ B ≥ C = D; F > B < E ≤ G
Conclusions:
I.G > A
II.D < F

3.
Statements:
I < J > K < L; M > K = N ≤ O
Conclusions:
I.J > O
II.M > L

4.
Statements:
X < Y = Z ≥ A; U < V ≥ Y = W
Conclusions:
I.W > A
II.A = W

5.
Statements:
M = N > O ≤ P; Q ≤ R < N > S
Conclusions:
I.N < Q
II.M > Q

Directions:(6-10) In each of the following questions, relationship between different elements is shown in the statements followed by two conclusions. Find the conclusion which is definitely true.
6.
Statements:
Q < D ≤ B ≥ M = N;                 C > Z ≥ V > D;               Y > J = V ≥ H
Conclusions:
I. J > Q
II. M > C

7.
Statements:
Y > T ≥ R ≥ E > Q;                  H < G ≥ E = W;              W < C < X ≤ Z
Conclusions:
I. W < G
II. G = W

8.
Statements:
L < K ≤ H < J = F;          V > B ≥ H > M;               T > O = I ≥ B
Conclusions:
I. I > H
II. V > L

9.
Statements:
E < D = C < R ≤ F;                  V < F ≥ G = N;               U > J > M < V
Conclusions:
I. F > J
II. G < R

10.
Statements:
M = J ≤ U < Y < T;                   G > H ≥ Y > L;                C > N = H ≥ B
Conclusions:
I. G > N
II. C > M

Directions:(1-10) In these questions, relationship between different elements is shown in the statements. These statements are followed by two conclusions.

##### 1. Question

Statements:
P ≤ Q < R > S; T ≥ Q < U = V
Conclusions:
I. V > P
II. R < U

Ans: 2
P ≤ Q < R > S; T ≥ Q < U = V
I. V > P (P ≤ Q < U = V) –>True
II. R < U (R > Q < U) –> False

##### 2. Question

Statements:
A ≤ B ≥ C = D; F > B < E ≤ G
Conclusions:
I.G > A
II.D < F

Ans: 1
A ≤ B ≥ C = D; F > B < E ≤ G
I.G > A (A ≤ B < E ≤ G) –> True
II.D < F (D = C ≤ B < F) –> True

##### 3. Question

Statements:
I < J > K < L; M > K = N ≤ O
Conclusions:
I.J > O
II.M > L

Ans: 4
I < J > K < L; M > K = N ≤ O
I. J > O (J > K = N ≤ O) –> False
II. M > L (M > K < L) –> False

##### 4. Question

Statements:
X < Y = Z ≥ A; U < V ≥ Y = W
Conclusions:
I.W > A
II.A = W

Ans: 3
X < Y = Z ≥ A; U < V ≥ Y = W
I.W > A (W = Y = Z ≥ A) –> False
II.A = W (W = Y = Z ≥ A) –> False

##### 5. Question

Statements:
M = N > O ≤ P; Q ≤ R < N > S
Conclusions:
I.N < Q
II.M > Q

Ans: 5
M = N > O ≤ P; Q ≤ R < N > S
I.N < Q (N > R ≥ Q) –> False
II.M > Q (M = N > R ≥ Q) –> True

Directions:(6-10) In each of the following questions, relationship between different elements is shown in the statements followed by two conclusions. Find the conclusion which is definitely true.

##### 6. Question

Statements:
Q < D ≤ B ≥ M = N;                 C > Z ≥ V > D;               Y > J = V ≥ H
Conclusions:
I. J > Q
II. M > C

Ans: 1
I. J > Q (J = V > D > Q) –> True
II. M > C (C > Z ≥ V > D ≤ B ≥ M) –> False
So, only conclusion I follow.

##### 7. Question

Statements:
Y > T ≥ R ≥ E > Q;                  H < G ≥ E = W;              W < C < X ≤ Z
Conclusions:
I. W < G
II. G = W

Ans: 3
I. W < G (G ≥ E = W )–> False
II. G = W (G ≥ E = W) –> False
Since it follows either or condition; either conclusion I or II follows.

##### 8. Question

Statements:
L < K ≤ H < J = F;          V > B ≥ H > M;               T > O = I ≥ B
Conclusions:
I. I > H
II. V > L

Ans: 2
I. I > H (I ≥ B ≥ H) –> False
II. V > L (V > B ≥ H ≥ K > L) –> True
So, only conclusion II follows.

##### 9. Question

Statements:
E < D = C < R ≤ F;                  V < F ≥ G = N;               U > J > M < V
Conclusions:
I. F > J
II. G < R

Ans: 4
I. F > J (J > M < V < F) –> False
II. G < R (R ≤ F ≥ G) –> False
So, neither conclusion I nor II follows.

##### 10. Question

Statements:
M = J ≤ U < Y < T;                   G > H ≥ Y > L;                C > N = H ≥ B
Conclusions:
I. G > N
II. C > M

Ans: 5
I. G > N (G > H= N) –> True
II. C > M (C > N = H ≥ Y > U ≥ J = M) –> True
So, both conclusions I and II follow.