# Set-25 Quadratic Equations (Inequalities) For SBI PO and SBI Clerk 2019 | Must Go Through These Questions

Dear Aspirants,
We are providing the most important Quadratic Equations (Inequalities) for SBI PO 2019, SBI Clerk 2019 and all other competitive bank and insurance exams. These questions have very high chances to be asked in SBI PO 2019, SBI Clerk 2019.

Directions:1-5) In each of the following questions, two equations (i) and (ii) are given. Solve them and find the correct option.

1.
a) x4= 28561
b) [(y5/2)/√13] = [(2*4) +√25]2

2.
a)3x-2y=12
b)7x-6y=18

3.
a)8x2-34x=- 8
b)23y2-368=0

4.
a)x2+12x+36=0
b)y2+7y+6=0

5.
a)√360 x + (200)1/2=0
b)√500 y + √402=0

Directions:6-10) In each of these questions, two equations (I) and (II) are given. You have to solve both the equations and give answer.

6.
I.2x2 – 15x+ 28 = 0
II.10y2 – y- 119 = 0

7.
I.6x2 – 47x + 80 = 0
II.2y2 – 9y + 10 = 0

8.
I.20x2 – 51x + 27 = 0
II.15y2 – 16y + 4 = 0

9.
I.8x2 +10x -12 =0
II.7y2+25y+12=0

10.
I.4x+7y =14.03
II.3X+17y = -4.87A

Directions:1-5) In each of the following questions, two equations (i) and (ii) are given. Solve them and find the correct option.

##### 1. Question

a) x4= 28561
b) [(y5/2)/√13] = [(2*4) +√25]2

Ans:3
a)x4= 28561x= 13 and -13

b) [(y5/2)/√13] = [(2*4)+√25]2
[(y5/2)/√13]= [8+5]2
y5/2= 131/2(13)2
y=13
Hence x ≤ y

##### 2. Question

a)3x-2y=12
b)7x-6y=18

Ans:1
3x-2y=12………… (1)7x-6y=18………… (2)

Multiply (1) by 3 then we get,
9x-6y=36 ……………. (3)
After solving (2) and (3), we get, x=9 and y=7.5
Hence, x>y

##### 3. Question

a)8x2-34x=- 8
b)23y2-368=0

Ans:5
a)8x2-34x=-88x2-34x+8=0
8x2-32x-2x+8=0
8x(x-4)-2(x-4) =0
x=4 and ¼

b)23y2-368=0
23y2=368
y2=16
y=4 and -4
Hence, the relationship cannot be determined.

##### 4. Question

a)x2+12x+36=0
b)y2+7y+6=0

Ans:3
a)x2+12x+36=0x2+6x+6x+36=0
x(x+6)+6(x+6)=0
x=-6 and -6
b)y2+7y+6=0
y2 +y+6y+6=0
y(y+1)+6(y+1)=0
y=-1 and -6
Hence, x≤y

##### 5. Question

a)√360 x + (200)1/2=0
b)√500 y + √402=0

Ans:1
a)√360 x + (200)1/2=0√360 x=-√200
x=-0.74
b)√500 y + √402=0
√500 y= -√402
y=-√402/√500
y=-0.89
Hence, x>y

Directions:6-10) In each of these questions, two equations (I) and (II) are given. You have to solve both the equations and give answer.

##### 6. Question

I.2x2 – 15x+ 28 = 0
II.10y2 – y- 119 = 0

Ans:3
2x2 – 15x+ 28 = 0X = 4,7/2
10y2 – y- 119 = 0
Y = 7/2 ,-17/5
x ≥ y

##### 7. Question

I.6x2 – 47x + 80 = 0
II.2y2 – 9y + 10 = 0

Ans:3
6x2 – 47x + 80 = 0X= 16/3 , 5/2
2y2 – 9y + 10 = 0
Y = 5/2, 4/2
X ≥ y

##### 8. Question

I.20x2 – 51x + 27 = 0
II.15y2 – 16y + 4 = 0

Ans:1
20x2 – 51x + 27 = 0X = 9/5, 3/4
15y2 – 16y + 4 = 0
y= 2/5, 2/3
X>Y

##### 9. Question

I.8x2 +10x -12 =0
II.7y2+25y+12=0

Ans:5
8x2 +10x -12 =0X= -16/8, 6/8
X= -2, 0.75
7y2+25y+12=0
Y = -21/7, -4/7
= -3,-4/7

If x = y or relation cannot be established

##### 10. Question

I.4x+7y =14.03
II.3X+17y = -4.87A

Ans:1
X=5.8; Y = -1.31