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We are providing the most important **Quadratic Equations (Inequalities) for SBI PO 2019, SBI Clerk 2019** and all **other competitive bank and insurance exams**. These questions have very high chances to be asked in **SBI PO 2019, SBI Clerk 2019. **Get the

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Directions:1-5) **In each of the following questions, two equations (i) and (ii) are given. Solve them and find the correct option**.

1.

a) x^{4}= 28561

b) [(y^{5/2})/√13] = [(2*4) +√25]^{2}

2.

a)3x-2y=12

b)7x-6y=18

3.

a)8x^{2}-34x=- 8

b)23y^{2}-368=0

4.

a)x^{2}+12x+36=0

b)y^{2}+7y+6=0

5.

a)√360 x + (200)^{1/2}=0

b)√500 y + √402=0

Directions:6-10) **In each of these questions, two equations (I) and (II) are given. You have to solve both the equations and give answer.**

6.

I.2x^{2} – 15x+ 28 = 0

II.10y^{2} – y- 119 = 0

7.

I.6x^{2} – 47x + 80 = 0

II.2y^{2} – 9y + 10 = 0

8.

I.20x^{2} – 51x + 27 = 0

II.15y^{2} – 16y + 4 = 0

9.

I.8x^{2} +10x -12 =0

II.7y^{2}+25y+12=0

10.

I.4x+7y =14.03

II.3X+17y = -4.87A

**Check your Answers below:**

Directions:1-5) **In each of the following questions, two equations (i) and (ii) are given. Solve them and find the correct option**.

##### 1. Question

a) x^{4}= 28561

b) [(y^{5/2})/√13] = [(2*4) +√25]^{2}

a)x

^{4}= 28561x= 13 and -13

b) [(y^{5/2})/√13] = [(2*4)+√25]^{2 }[(y^{5/2})/√13]= [8+5]^{2 }y^{5/2}= 13^{1/2}(13)^{2 }y=13

Hence **x ≤ y**

##### 2. Question

a)3x-2y=12

b)7x-6y=18

3x-2y=12………… (1)7x-6y=18………… (2)

Multiply (1) by 3 then we get,

9x-6y=36 ……………. (3)

After solving (2) and (3), we get, x=9 and y=7.5

Hence, **x>y**

##### 3. Question

a)8x^{2}-34x=- 8

b)23y^{2}-368=0

a)8x

^{2}-34x=-88x

^{2}-34x+8=0

8x

^{2}-32x-2x+8=0

8x(x-4)-2(x-4) =0

x=4 and ¼

b)23y^{2}-368=0

23y^{2}=368

y^{2}=16

y=4 and -4

Hence, **the relationship cannot be determined.**

##### 4. Question

a)x^{2}+12x+36=0

b)y^{2}+7y+6=0

a)x

^{2}+12x+36=0x

^{2}+6x+6x+36=0

x(x+6)+6(x+6)=0

x=-6 and -6

b)y

^{2}+7y+6=0

y

^{2 }+y+6y+6=0

y(y+1)+6(y+1)=0

y=-1 and -6

Hence,

**x≤y**

##### 5. Question

a)√360 x + (200)^{1/2}=0

b)√500 y + √402=0

a)√360 x + (200)

^{1/2}=0√360 x=-√200

x=-0.74

b)√500 y + √402=0

√500 y= -√402

y=-√402/√500

y=-0.89

Hence,

**x>y**

Directions:6-10) **In each of these questions, two equations (I) and (II) are given. You have to solve both the equations and give answer. **

##### 6. Question

I.2x^{2} – 15x+ 28 = 0

II.10y^{2} – y- 119 = 0

2x

^{2}– 15x+ 28 = 0X = 4,7/2

10y

^{2}– y- 119 = 0

Y = 7/2 ,-17/5

x ≥ y

##### 7. Question

I.6x^{2} – 47x + 80 = 0

II.2y^{2} – 9y + 10 = 0

6x

^{2}– 47x + 80 = 0X= 16/3 , 5/2

2y

^{2}– 9y + 10 = 0

Y = 5/2, 4/2

X ≥ y

##### 8. Question

I.20x^{2} – 51x + 27 = 0

II.15y^{2} – 16y + 4 = 0

20x

^{2}– 51x + 27 = 0X = 9/5, 3/4

15y

^{2}– 16y + 4 = 0

y= 2/5, 2/3

X>Y

##### 9. Question

I.8x^{2} +10x -12 =0

II.7y^{2}+25y+12=0

8x

^{2}+10x -12 =0X= -16/8, 6/8

X= -2, 0.75

7y

^{2}+25y+12=0

Y = -21/7, -4/7

= -3,-4/7

If x = y or relation cannot be established

##### 10. Question

I.4x+7y =14.03

II.3X+17y = -4.87A

X=5.8; Y = -1.31