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We are providing the most important **Quadratic Equations (Inequalities) for SBI PO 2019, SBI Clerk 2019** and all **other competitive bank and insurance exams**. These questions have very high chances to be asked in **SBI PO 2019, SBI Clerk 2019.
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Directions:1-10) **In each of the following questions, two equations(i) and (ii) are given. You have to solve them and find the correct option**.

1.

a) x^{3 }– 39304 = 0

b) y^{2 }– 1296=0

2.

a) 624-342-120+88x =784+248+516+22

b) (21y-504)(18y-576)=0

3.

a) 26x^2-64x+24=0

b) 2y^2-28y+96=0

4.

a) 16y + 10x=48

b) 8y+7x=32

5.

a) 2x^2+11x+9=0

b)2y^2-7y+6=0

Direction (6-10): **In the following questions, two equations I and II are given. You have to solve both the equations.
**

**Give Answer**

6.**
**I. p

^{2}– 18p + 72= 0

II. 5q

^{2}– 18q + 9 = 0

7.

I. p^{2} = 4

II. 3q^{2} – 4q – 4 = 0

8.

I. 6p^{2} – 5p – 6 = 0

II. 2q^{2} – 13q + 20 = 0

9.

I. 2p^{2} – 5p = 0

II. 3q^{2} – 7q – 6 = 0

10.

I. 2p^{2} + 5p + 2= 0

II. 2q^{2} + 19q + 45 = 0

**Check your Answers below:**

Directions:1-10) **In each of the following questions, two equations(i) and (ii) are given. You have to solve them and find the correct option**.

##### 1. Question

a) x^{3 }– 39304 = 0

b) y^{2 }– 1296=0

a) x

^{3 }– 39304 = 0

x

^{3 }= 39304

x=34

b) 2y^{2 }– 5184=0

y^{2 }=1296

y=±36

Thus, the relationship cannot be determined.

##### 2. Question

a) 624-342-120+88x =784+248+516+22

b) (21y-504)(18y-576)=0

a) 624-342-120+88x =784+248+516+22

624+88x= 2032

88x=1408

x=16

b) (21y-504)(18y-576)=0

21y- 504=0, 18y-576=0

21y=504, 18y=576

y=24 and 32

Thus **x<y**

##### 3. Question

a) 26x^2-64x+24=0

b) 2y^2-28y+96=0

a) 26x^2-64x+24=0

13x^2-32x+12=0

(X-2)(13x-6)=0

x=2 and 6/13

b) 2^2-28y+96=0

y^2-14y+48=0

(y-6)(y-8)=0

y=6 and 8

Thus **x<y**

##### 4. Question

a) 16y + 10x=48

b) 8y+7x=32

10x+16y=48……(1)

7x+8y=32………(2)

Multiplying (2) by 2 and solving equations, we get

x=4 and y=0.5

Thus

**x>y**

##### 5. Question

a) 2x^2+11x+9=0

b)2y^2-7y+6=0

a) 2x^2+11x+9=0

2x(x+1) +9(x+1) =0

(x+1)(2x+9)=0

x=-4.5 and -1

b) 2y^2-7y+6=0

2y^2-4y-3y+6=0

2y(y-2)-3(y-2) =0

y=1.5 and 2

Thus **x<y**

Direction (6-10): **In the following questions, two equations I and II are given. You have to solve both the equations.
**

**Give Answer**

##### 6. Question

I. p^{2} – 18p + 72= 0

II. 5q^{2} – 18q + 9 = 0

p

^{2}– 18p + 72= 0

(p-12)(p-6) = 0

Gives p = 6, 12

5q

^{2}– 18q + 9 = 0

5q

^{2}– 15q – 3q + 9 = 0

5q (q-3) – 3(q-3) =0

(5q-3) (q-3) =0

Gives q = 3/5, 3

Put on number line

3/5 3 6 12

P > q

##### 7. Question

I. p^{2} = 4

II. 3q^{2} – 4q – 4 = 0

p

^{2}= 4

Gives p = 2 , -2

3q

^{2}– 4q – 4 = 0

3q

^{2}– 6q + 2q – 4 = 0

Gives q = -2/3, 2

Put on number line

-2 -2/3 2

So no relation

##### 8. Question

I. 6p^{2} – 5p – 6 = 0

II. 2q^{2} – 13q + 20 = 0

6p

^{2}– 5p – 6 = 0

6p

^{2}– 9p + 4p – 6 = 0

Gives p = -2/3, 3/2

2q

^{2}– 13q + 20 = 0

2q

^{2}– 8q – 5q +20 = 0

Gives q = 4, 5/2

Put on number line

-2/3 3/2 5/2 4

P < q

##### 9. Question

I. 2p^{2} – 5p = 0

II. 3q^{2} – 7q – 6 = 0

2p

^{2}– 5p = 0

p(2p-5) = 0

Gives p = 0, 5/2

3q

^{2}– 7q – 6 = 0

3q

^{2}– 9q + 2q – 6 = 0

Gives q = -2/3, 3

Put on number line

-2/3 0 5/2 3

There is no relation

##### 10. Question

I. 2p^{2} + 5p + 2= 0

II. 2q^{2} + 19q + 45 = 0

2p

^{2}+ 5p + 2= 0

2p

^{2}+ 4p + p + 2= 0

Gives p = -1/2, -2

2q

^{2}+ 19q + 45 = 0

2q

^{2}+ 10q + 9q + 45 = 0

Gives q= -10/2, -9/2

Put on number line

-10/2 -9/2 -2 -1/2

P > q