Set-8 Quadratic Equations (Inequalities) For SBI PO and SBI Clerk 2019 | Must Go Through These Questions

• x > y
• x < y
• x ≤ y
• x ≥y
• x = y Or cannot be determined

8.

• Directions:1-10) In each of the following questions, two equations (a) and (b) are given. Solve them and find the correct option.

  1. Question

  I. x⁴= 28561

  II. [(y^5/2)/√13] = [(2*4) +√25]²

  • x>y
  • x<y
  • x ≤ y
  • x ≥y
  • x=y Or cannot be determined
  Ans:3
  I. x⁴= 28561

  x= 13 and -13

  II. [(y^5/2)/√13] = [(2*4)+√25]²

  [(y^5/2)/√13]= [8+5]²

  y^5/2= 13^1/2(13)²

  y=13

  Hence x ≤ y

• 2. Question

  I. 3x-2y=12

  II. 7x-6y=18

  • x>y
  • x<y
  • x ≤ y
  • x ≥y
  • x=y Or cannot be determined
  Ans:1
  3x-2y=12………… (1)

  7x-6y=18………… (2)

  Multiply (1) by 3 then we get,

  9x-6y=36 ……………. (3)

  After solving (2) and (3), we get, x=9 and y=7.5

  Hence, x>y

• 3. Question

  I. 8x²-34x=- 8

  II. 23y²-368=0

  • x>y
  • x<y
  • x ≤ y
  • x ≥y
  • x=y Or cannot be determined
  Ans:5
  I. 8x²-34x=-8

  8x²-34x+8=0

  8x²-32x-2x+8=0

  8x(x-4)-2(x-4) =0

  x=4 and ¼

  II. 23y²-368=0

  23y²=368

  y²=16

  y=4 and -4

  Hence, the relationship cannot be determined

• 4. Question

  I. x²+12x+36=0

  II. y²+7y+6=0

  • x>y
  • x<y
  • x ≤ y
  • x ≥y
  • x=y Or cannot be determined
  Ans:3
  I. x²+12x+36=0

  x²+6x+6x+36=0

  x(x+6)+6(x+6)=0

  x=-6 and -6

  II. y²+7y+6=0

  y² +y+6y+6=0

  y(y+1)+6(y+1)=0

  y=-1 and -6

  Hence, x≤y

• 5. Question

  I. √360 x + (200)^1/2=0

  II. √500 y + √402=0

  • x>y
  • x<y
  • x ≤ y
  • x ≥y
  • x=y Or cannot be determined
  Ans:1
  I. √360 x + (200)^1/2=0

  √360 x=-√200

  x=-0.74

  II. √500 y + √402=0

  √500 y= -√402

  y=-√402/√500

  y=-0.89

  Hence, x>y

• 6. Question

  a)x³ – 39304 = 0

  b)y² – 1296=0

  • x > y
  • x < y
  • x ≤ y
  • x ≥y
  • x = y Or cannot be determined
   Ans:5
  x³ – 39304 = 0

  x³ = 39304

  x=34

  2y² – 5184=0

  y² =1296

  y=±36

  Thus, the relationship cannot be determined.

• 7. Question

  a)624-342-120+88x=784+248+516+22

  b)(21y-504)(18y-576)=0

  • x > y
  • x < y
  • x ≤ y
  • x ≥y
  • x = y Or cannot be determined
   Ans:2
  624-342-120+88x =784+248+516+22

  624+88x= 2032

  88x=1408

  x=16

  (21y-504)(18y-576)=0

  21y- 504=0, 18y-576=0

  21y=504, 18y=576

  y=24 and 32

  Thus x<y

• 8. Question

  a)26x²-64x+24=0

  b)2y²-28y+96=0

  • x > y
  • x < y
  • x ≤ y
  • x ≥y
  • x = y Or cannot be determined
  Ans:2
  26x²-64x+24=0

  13x²-32x+12=0

  (X-2)(13x-6)=0

  x=2 and 6/13

  b) 2²-28y+96=0

  y²-14y+48=0

  (y-6)(y-8)=0

  y=6 and 8

  Thus x<y

• 9. Question

  a)16y + 10x=48

  b)8y+7x=32

  • x > y
  • x < y
  • x ≤ y
  • x ≥y
  • x = y Or cannot be determined
  Ans:1
  10x+16y=48……(1)

  7x+8y=32………(2)

  Multiplying (2) by 2 and solving equations, we get

  x=4   and    y=0.5

  Thus x>y

• 10. Question

  a)2x²+11x+9=0

  b)2y²-7y+6=0

  • x > y
  • x < y
  • x ≤ y
  • x ≥y
  • x = y Or cannot be determined
  Ans:2
  2x²+11x+9=0

  2x(x+1) +9(x+1) =0

  (x+1)(2x+9)=0

  x=-4.5 and -1

  2y²-7y+6=0

  2y²-4y-3y+6=0

  2y(y-2)-3(y-2) =0

  y=1.5 and 2

  Thus x<y